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Relationship between Unequal Sides of Triangle and the Angles Opposite to It.

Question

In $Δ P Q R,$ if $∠ R > ∠ Q,$ then:
$Q R > P R$
$P Q < P R$
$Q R < P R$
$P Q > P R$

A

P Q > P R

B

Q R < P R

C

Q R > P R

D

P Q < P R

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Solution

Verified by Toppr

We k ow that the side opposite to the greater angle is greater.
Given, $∠ R > ∠ Q$
Thus, $P Q > P R$ .
Hence, option $B$ is correct.

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Similar Questions

Q1

Question 9
In

Δ P Q R

, if

∠ R > ∠ Q

, then
(A) QR > PR
(B) PQ > PR
(C) PQ < PR
(D) QR < PR

View Solution

Q2

A =

⎡ ⎢ ⎣ \begin{matrix} - q r & p (q + r) & p r + p q p q + q r & - p r & p q + q r q r + p r & q r + p r & - p q \end{matrix} ⎤ ⎥ ⎦

then

| A |

equals:

View Solution

Q3

Simplify:

(p q - q r + p r) (p q + q r) - (p r + p q) (p + q - r)

View Solution

Q4

Question 9

In $Δ P Q R$ ,

a) PQ - QR > PR
b) PQ + QR < PR
c) PQ - QR < PR
d) PQ + PR < QR

View Solution

Q5

Draw

∆

PQR in which QR = 5 cm, PR

-

PQ = 2.5 cm

∠

Q

-

∠

R = 52

°

View Solution