In fig- a circle touches all the four sides of a quadrilateral ABCD in which AB - 6 cm- BC - 7 cm and CD - 4 cm- Find AD-

Question

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Given-AB-6cm-BC-7cm-CD-4cm-We know that-boxed-text-When a circle inscribed in a quadrilateral ABCD touching all the four sides then AB-CD - BC-AD-Rightarrow 6-4-7-AD-Rightarrow 10-7-AD-Rightarrow AD-10-7-Rightarrow AD-3-

In fig., a circle touches all the four sides of a quadrilateral $$ABCD$$ in which $$AB = 6 cm, BC = 7 cm$$ and $$CD = 4 cm$$. Find $$AD$$.

Given,
$$AB=6cm,BC=7cm,CD=4cm$$
We know that
$$\boxed{\text{When a circle inscribed in a quadrilateral ABCD touching all the four sides then AB+CD = BC+AD}}$$
$$\Rightarrow 6+4=7+AD$$
$$\Rightarrow 10=7+AD$$
$$\Rightarrow AD=10-7$$
$$\Rightarrow AD=3$$

In fig., a circle touches all the four sides of a quadrilateral $$ABCD$$ in which $$AB = 6 cm, BC = 7 cm$$ and $$CD = 4 cm$$. Find $$AD$$.

Given,$$AB=6cm,BC=7cm,CD=4cm$$We know that$$\boxed{\text{When a circle inscribed in a quadrilateral ABCD touching all the four sides then AB+CD = BC+AD}}$$$$\Rightarrow 6+4=7+AD$$$$\Rightarrow 10=7+AD$$$$\Rightarrow AD=10-7$$$$\Rightarrow AD=3$$

Given,
$$AB=6cm,BC=7cm,CD=4cm$$
We know that
$$\boxed{\text{When a circle inscribed in a quadrilateral ABCD touching all the four sides then AB+CD = BC+AD}}$$
$$\Rightarrow 6+4=7+AD$$
$$\Rightarrow 10=7+AD$$
$$\Rightarrow AD=10-7$$
$$\Rightarrow AD=3$$