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Question

In Fig., ABC is the cross section of a right-angled prism and ACDE is the cross section of a glass slab. The value of θ so that light incident normally on the face AB does not cross the face AC is (given sin1(3/5)=37).
159448_c7ecf8e9f2f94136b55543418f28fa0a.png
  1. θ<37
  2. θ53
  3. θ<53
  4. θ37

A
θ37
B
θ<53
C
θ<37
D
θ53
Solution
Verified by Toppr

For the light to not cross the surface AC, there must be a total internal reflection at the interface.
Thus sini>μ2μ1=45

Hence, i>53

Hence, θ<37

407187_159448_ans_fdf05047715d47aea11375ddfcb127aa.png

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