Question

In Fig., find the area of parallelogram ABCD if the area of shaded triangle is $$9\, cm^2$$.

Answer 1

Given, Area of shaded portion $$= 9 \,sq.\, cm$$

Base of triangle $$= 3\, cm$$

Now, area of triangle$$=9$$,

$$\Rightarrow 9 = \cfrac {1}{2} \times 3 \times h $$

$$\Rightarrow h = \cfrac {18}{3}$$

$$\Rightarrow h = 6\, cm$$

Area of parallelogram $$=\text{Base x Height}= BC\times h$$

$$=(3+4)\times 6 =7\times 6 =42\, cm^2$$