Question

# In fig For an angle of incidence 45∘ at top surface what is the minimum refractive index needed for total internal reflection at vertical face AD? A
1/2
B
2
C
3/2
D
2+12
Solution
Verified by Toppr

#### The correct option is C√3/2AT point of A by snell'sμ=sin450sinr⇒sinr=1μ√2..........(1)From figure,i1=90−r∴sin(900−r)=1μNow,⇒cosr=1μ..........(2)cosr=√1−sin2r=√1−12μ2=√2μ2−12μ2...........(3)fromequation(2)and(3)1μ=√2μ2−12μ2Squaring both sides then solving we get =√32

0
Similar Questions
Q1

A ray of light is incident at an angle of 45 on a square slab of a transparent material. What should be the refractive index of the material of the slab so that total internal reflection occurs at the vertical face AB? View Solution
Q2

In the figure shown, for an angle of incidence 45, at the top surface, what is the minimum refractive index needed for total internal reflection at vertical face AD ? View Solution
Q3

For an angle of incidence of 45o at the top of surface of a glass slab as shown in figure, what is the maximum refractive index of glass for total internal reflection? [For water μ=43] View Solution
Q4

In the figure given below, for an angle of incidence 45o at the top surface, what is the minimum refractive index need to total internal reflection at vertical face? View Solution
Q5

Kelper used total internal reflection in a glass block to deflect a beam of light as shown in the figure. For an angle of the incidence i at the top surface, the minimum refractive index (n) needed for total internal reflection at the vertical surface is (the surrounding medium is air for which n=1) View Solution
Solve
Guides