In fig AB parallel DE- angle BAC - 35-circ- and angle CDE - 53-circ- angle DCE in degrees-

Question

Toppr Admin · Accepted Answer

Given- AB-x2225-DE-x2220-BAC-x2220-CED-35-x2218- -Alternate angles of parallel lines AB and DE-In -x25B3-CDE-x2220-CDE-x2220-DCE-x2220-CED-18053-35-x2220-DCE-180-x2220-DCE-180-x2212-88-x2220-DCE-92-x2218-

In fig if $A B$ $∥$ $D E$ , $∠ B A C = 35^{\circ}$ and $∠ C D E = 53^{\circ}$ , find $∠ D C E$ in degrees.

Given, $A B ∥ D E$ ,
$∠ B A C = ∠ C E D = 35^{\circ}$ (Alternate angles of parallel lines AB and DE)
In $△ C D E$ ,
$∠ C D E + ∠ D C E + ∠ C E D = 180$
$53 + 35 + ∠ D C E = 180$
$∠ D C E = 180 - 88$
$∠ D C E = 92^{\circ}$

In fig if AB ∥ DE, ∠BAC=35∘ and ∠CDE=53∘, find ∠DCE in degrees.

Given, AB∥DE,∠BAC=∠CED=35∘ (Alternate angles of parallel lines AB and DE)In △CDE,∠CDE+∠DCE+∠CED=18053+35+∠DCE=180∠DCE=180−88∠DCE=92∘

In fig if $A B$ $∥$ $D E$ , $∠ B A C = 35^{\circ}$ and $∠ C D E = 53^{\circ}$ , find $∠ D C E$ in degrees.

Given, $A B ∥ D E$ ,
$∠ B A C = ∠ C E D = 35^{\circ}$ (Alternate angles of parallel lines AB and DE)
In $△ C D E$ ,
$∠ C D E + ∠ D C E + ∠ C E D = 180$
$53 + 35 + ∠ D C E = 180$
$∠ D C E = 180 - 88$
$∠ D C E = 92^{\circ}$