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Question

In Fig.,
(i) $$\angle TPQ = \angle$$ ______ $$+ \angle$$ ______
(ii) $$\angle UQR = \angle$$ ______ $$+ \angle$$ ______
(iii) $$\angle PRS = \angle$$ ______ $$+ \angle$$ ______

Solution
Verified by Toppr

We know that,
Exterior angle= Sum of opposite interior angles [By exterior angle property]

Hence,
(i) $$\angle TPQ = \angle PQR + \angle PQR$$
(ii) $$\angle UQR = \angle QPR + \angle QPR$$
(iii) $$\angle PRS = \angle RPQ + \angle ROP$$

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Similar Questions
Q1
In Fig.,
(i) $$\angle TPQ = \angle$$ ______ $$+ \angle$$ ______
(ii) $$\angle UQR = \angle$$ ______ $$+ \angle$$ ______
(iii) $$\angle PRS = \angle$$ ______ $$+ \angle$$ ______

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Q2

Question 69

Fill in the blanks to make the statement true.

In the given figure,
i) TPQ= ___ + ___
ii) UQR= ___ + ___
iii) PRS= ___ + ___


View Solution
Q3

Question 69

Fill in the blanks to make the statement true.

In the given figure,
i) TPQ= ___ + ___
ii) UQR= ___ + ___
iii) PRS= ___ + ___

View Solution
Q4

In Fig. PQRS is a quadrilateral in which diagonals PR and QS intersect in O.


Show that:
(i) PQ + QR + RS + SP >PR + QS
(ii) PQ + QR + RS + SP <2 (PR + QS)


View Solution
Q5
From the choices given below, choose the equation whose graphs are given in Fig. (i) and Fig. (ii).

For fig. (i) For fig. (ii)
(i) y=x (i) y=x+2
(ii) x+y=0 (ii) y=x2
(iii) y=2x (iii) y=x+2
(iv) 2+3y=7x (iv) x+2y=6

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