In Figure 1- the lateral area of the right circular cone is 60pi- If the radius of the base is 6- calculate the volume of the cone-96 pi108 pi120 pi184 pi

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Toppr Admin · Accepted Answer

Given- radius of base -6Lateral area of a cone is -x3C0-rl-60-x3C0-xA0-x21D2-rl-60-x21D2-l-606-x21D2-l-10-x2234-h-x221A-l2-x2212-r2-8Volume of cone is -x3C0-r2h3-96-x3C0-

In Figure 1, the lateral area of the right circular cone is $60 π$ . If the radius of the base is $6$ , calculate the volume of the cone.

$96 π$
$108 π$
$120 π$
$184 π$

Given, radius of base $= 6$
Lateral area of a cone is $π r l = 60 π$
$\Rightarrow r l = 60$
$\Rightarrow l = \frac{60}{6}$
$\Rightarrow l = 10$
$∴ h = \sqrt{l^{2} - r^{2}} = 8$
Volume of cone is $\frac{π r^{2} h}{3} = 96 π$

In Figure 1, the lateral area of the right circular cone is 60π. If the radius of the base is 6, calculate the volume of the cone.96π108π120π184π

Given, radius of base =6Lateral area of a cone is πrl=60π ⇒rl=60⇒l=606⇒l=10∴h=√l2−r2=8Volume of cone is πr2h3=96π

In Figure 1, the lateral area of the right circular cone is $60 π$ . If the radius of the base is $6$ , calculate the volume of the cone.

$96 π$
$108 π$
$120 π$
$184 π$

Given, radius of base $= 6$
Lateral area of a cone is $π r l = 60 π$
$\Rightarrow r l = 60$
$\Rightarrow l = \frac{60}{6}$
$\Rightarrow l = 10$
$∴ h = \sqrt{l^{2} - r^{2}} = 8$
Volume of cone is $\frac{π r^{2} h}{3} = 96 π$