In Figure 3-11 - line AB - - - line CD and line - P Q - is the transversal- Ray - P T - and ray QTare bisectors of - angle mathrm - BPQ - - and - angle P Q D - respectively Prove that - mathrm - m - angle mathrm - PTQ - - 90 - - circ - - - A - - i Q -

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Toppr Admin · Accepted Answer

In Figure 3.11 , line AB \( \| \) line CD and line \( P Q \) is the transversal. Ray \( P T \) and ray QTare bisectors of \( \angle \mathrm { BPQ } \) and \( \angle P Q D \) respectively Prove that \( \mathrm { m } \angle \mathrm { PTQ } = 90 ^ { \circ } \) \( A \) \( i Q \)