and we know that sum of angles in a straight line is $$180^o$$
let the unknown angle be $$x$$
$$\angle 1:\angle 2= 3x : 2x$$
$$\angle 1+\angle 2=180^o$$
$$ 3x+2x=180^o$$
$$5x=180^o$$
$$x=36^o$$
=> $$\angle 1 = 3 \times 36^o=108^o$$
=> $$\angle 2 = 2 \times 36^o=72^o$$
We know that vertically opposite angles are equal.
$$\angle 1=\angle 3= 108^o$$
$$\angle 2=\angle 4= 71^o$$
We know that corresponding angles are equal.
$$\angle 1=\angle 5= 108^o$$
$$\angle 2=\angle 6= 71^o$$
$$\angle 4=\angle 8= 71^o$$
$$\angle 3=\angle 7= 108^o$$
$$\therefore$$ $$\angle 1=\angle 5=\angle 3=\angle 7= 108^o$$ and
$$\angle 2=\angle 6 = \angle 4=\angle 8= 71^o$$