Solve
Guides
0
Question
In figure, find $$\angle x$$. Further find $$\angle BOC, \angle COD$$ and $$\angle AOD$$.
Open in App
Solution
Verified by Toppr
We know that the sum of all the angles in a straight line is $$180^o$$
$$\angle BOC + \angle COD + \angle AOD = 180^o$$.
$$x +20 +x + x+10 = 180^o $$
$$3x +30 = 180^o $$
$$3x = 150^o $$
$$x = 50^o $$
$$\angle COD = 50^o$$
$$ \angle AOD = x+10 ^o$$
$$=60^o$$
$$ \angle BOC = x+20 ^o$$
$$=70^o$$
$$\therefore $$ $$\angle COD = 50^o$$, $$ \angle AOD = 60^o $$ and $$ \angle BOC = 70^o $$.
$$\angle BOC + \angle COD + \angle AOD = 180^o$$.
$$x +20 +x + x+10 = 180^o $$
$$3x +30 = 180^o $$
$$3x = 150^o $$
$$x = 50^o $$
$$\angle COD = 50^o$$
$$ \angle AOD = x+10 ^o$$
$$=60^o$$
$$ \angle BOC = x+20 ^o$$
$$=70^o$$
$$\therefore $$ $$\angle COD = 50^o$$, $$ \angle AOD = 60^o $$ and $$ \angle BOC = 70^o $$.
Was this answer helpful?
36
Similar Questions
Q1
In figure, find $$\angle x$$. Further find $$\angle BOC, \angle COD$$ and $$\angle AOD$$.
View Solution
Q2
In the figure, find x, further find ∠BOC,∠COD and ∠AOD.
View Solution
Q3
In the given figure, find x. Further find ā BOC, ā COD andā AOD
