In figure- it is given that AB-CD and AD -BC- Prove that triangle ADC cong triangle CBA-

Question

Toppr Admin · Accepted Answer

In -x394-ADC and -x394-CBA-AB-CD-xA0- -xA0- -Given-AD-BC-xA0- -xA0- -Given-CA-CA-xA0- -xA0- -common-Hence -x394-ADC-x2245-x394-CBA by SSS congruence rule

In figure, it is given that $A B = C D$ and $A D = B C$ . Prove that $△ A D C ≅ △ C B A$ .

In $Δ A D C$ and $Δ C B A$

$A B = C D$ (Given)

$A D = B C$ (Given)

$C A = C A$ (common)

Hence $Δ A D C ≅ Δ C B A$ by SSS congruence rule

In figure, it is given that AB=CD and AD=BC. Prove that △ADC≅△CBA.

In ΔADC and ΔCBA AB=CD (Given) AD=BC (Given) CA=CA (common) Hence ΔADC≅ΔCBA by SSS congruence rule

In figure, it is given that $A B = C D$ and $A D = B C$ . Prove that $△ A D C ≅ △ C B A$ .

In $Δ A D C$ and $Δ C B A$

$A B = C D$ (Given)

$A D = B C$ (Given)

$C A = C A$ (common)

Hence $Δ A D C ≅ Δ C B A$ by SSS congruence rule