In given figure, PB and Qa are perpendiculars to segment AB. If PO=5 cm, QO=7 cm and Area △POB=150cm2 find the area of △QOA.
Open in App
Solution
Verified by Toppr
In △OAQ and △OBP, we have
∠A=∠B [Each equal to 90∘]
∠AOQ=∠BOP
So, by AA-criterion of similarity, we have
△AOQ∼△BOP
⇒Area(△AOQ)Area(BOP)=OQ2OP2
⇒Area(△AOQ)150=7252
⇒Area(△AOQ)=4925×150cm2=294cm2
Was this answer helpful?
28
Similar Questions
Q1
In given figure, PB and Qa are perpendiculars to segment AB. If PO=5 cm, QO=7 cm and Area △POB=150cm2 find the area of △QOA.
View Solution
Q2
In fig., PB and QA are perpendiculars to segment AB. If PO = 5 cm, QO = 7 cm and
Area △POB = 150 cm2 find the area of △QOA.
View Solution
Q3
In the given figure, PB and QA are perpendicular to line segment AB. If PO=7cm, QO=12cm, and area of ΔPOB=245cm2, find the area of ΔQOA.
[2 marks]
View Solution
Q4
In the figure given below, sides PB and QA are perpendiculars drawn to the line segment AB.
If PO = 6 cm, QO = 9 cm, and area of ΔPOB=120cm2, then find the area of ΔQOA.
View Solution
Q5
In the figure, PB and QA are perpendicular to segment AB. If OA = 5 cm, PO = 7cm and area (ΔQOA) = 150 cm2, find the area of ΔPOB.