In half wave rectifier- a p-n diode with internal resistance 20 Omega is used- If the load resistance of 2 KOmega is used in the circuit- then the efficiency of this half wave rectifier is -in percentage-80-4-40-2-20-50-

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Toppr Admin · Accepted Answer

The efficiency-xA0-x3B7-xA0-of half wave rectifier is given by-xA0-x3B7-0-406RLrf-RL

In half wave rectifier, a p-n diode with internal resistance $20$ $Ω$ is used. If the load resistance of $2 K Ω$ is used in the circuit, then the efficiency of this half wave rectifier is (in percentage)
$80.4 %$
$40.2 %$
$20 %$
$50 %$

The efficiency $η$ of half wave rectifier is given by, $η = \frac{0.406 R_{L}}{r_{f} + R_{L}}$

In half wave rectifier, a p-n diode with internal resistance 20 Ω is used. If the load resistance of 2 KΩ is used in the circuit, then the efficiency of this half wave rectifier is (in percentage)80.4%40.2%20%50%

The efficiency η of half wave rectifier is given by, η=0.406RLrf+RL

In half wave rectifier, a p-n diode with internal resistance $20$ $Ω$ is used. If the load resistance of $2 K Ω$ is used in the circuit, then the efficiency of this half wave rectifier is (in percentage)
$80.4 %$
$40.2 %$
$20 %$
$50 %$

The efficiency $η$ of half wave rectifier is given by, $η = \frac{0.406 R_{L}}{r_{f} + R_{L}}$