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Question

In Hardy-Weinberg equation, the frequency of heterozygous individual is represented by
  1. pq
  2. q2
  3. 2pq
  4. p2

A
pq
B
q2
C
p2
D
2pq
Solution
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Hardy-Weinberg equation is p2 + 2pq + q2 = 1. Here, p is the frequency of the "A" allele and q is the frequency of the "a" allele in the population. Thus, p2 represents the frequency of the homozygous genotype AA, q2 is the frequency of the homozygous genotype aa, and 2pq represents the frequency of the heterozygous genotype Aa.

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