In NO-3- ion- the number of bond pairs and lone pairs of electrons on nitrogen atom are-3- 13- 01- 32- 2

Question

Toppr Admin · Accepted Answer

Total number of -x3C3- bonds -3So- the bond pairs -3 and lone pairs -0-So the correct option is -D-Note- To determine lone pairs draw the structure of NO-x2212-3 ion-

In $N O_{3}^{-}$ ion, the number of bond pairs and lone pairs of electrons on nitrogen atom are:
3, 1
3, 0
1, 3
2, 2

Total number of $σ$ bonds $= 3$

So, the bond pairs $= 3$ and lone pairs $= 0$ .

So the correct option is [D],

Note: To determine lone pairs draw the structure of $N O_{3}^{-}$ ion.

In NO3− ion, the number of bond pairs and lone pairs of electrons on nitrogen atom are:3, 13, 01, 32, 2

Total number of σ bonds =3So, the bond pairs =3 and lone pairs =0.So the correct option is [D],Note: To determine lone pairs draw the structure of NO−3 ion.

In $N O_{3}^{-}$ ion, the number of bond pairs and lone pairs of electrons on nitrogen atom are:
3, 1
3, 0
1, 3
2, 2

Total number of $σ$ bonds $= 3$

So, the bond pairs $= 3$ and lone pairs $= 0$ .

So the correct option is [D],

Note: To determine lone pairs draw the structure of $N O_{3}^{-}$ ion.