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Question

In nuclear reaction $_{4} B e^{9} +_{2} H e^{4} \to_{6} c^{12}$ +X, X will be :
Proton
Neutron
$β$ -particle
$α$ -particle

A

Neutron

B

β

-particle

C

Proton

D

α

-particle

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Solution

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$_{4} B e^{9} +_{2} H e^{4} \to_{6} C^{12} + X$

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