In PCl-5- phosphorous is in sp-3d hybridized state but all its five bonds are not equivalent- Justify answer with reason-

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In gaseous and liquid phases- it has a trigonal bipyramidal structure as shown- The three equatorial P-8722-Cl bonds are equivalent- while the two axial bonds are longer than equatorial bonds- This is due to the fact that the axial bond pairs suffer more repulsion as compared to equatorial bond pairs-

In $$PCl_5$$, phosphorous is in $$sp^3d$$ hybridized state but all its five bonds are not equivalent. Justify answer with reason.

In gaseous and liquid phases, it has a trigonal bipyramidal structure as shown. The three equatorial P−Cl bonds are equivalent, while the two axial bonds are longer than equatorial bonds. This is due to the fact that the axial bond pairs suffer more repulsion as compared to equatorial bond pairs.