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Question

In photoelectric effect, the slope of the straight line graph between stopping potential and frequency of the incident light gives the ratio of Planck's constant to
  1. Work function
  2. K.E. of electron
  3. Charge of electron
  4. Photoelectric current

A
K.E. of electron
B
Charge of electron
C
Work function
D
Photoelectric current
Solution
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hv=hv0+K.E
at stopping potential K.E=eV
hv=hv0+eV

V=he(vv0)

The slope of graph b/w stopping potential and frequency is he, where e is charge of electron.

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