Solve
Guides
0
Question
"In rigelt triangle \\( A B C \\), right angle is at \\( c , \\mu \\)\nis the mid-point of hypotemise \\( A B \\cdot c \\) is\njoind to \\( M \\) and produce \\( A B \\), point \\( D \\)\nsuch that \\( \\quad D M = C M \\). Point \\( D \\) is a point to\npoint \\( B \\) (see tigure). Susw in in\npoint \\( B \\) (sinp\n(ii) \\( \\angle D B C \\) is a rigut angle\n(iii) \\( \\triangle D B C = \\triangle A C B \\)\n(ii) \\( C M = \\frac { 1 } { 2 } A B \\)"
Open in App
Solution
Verified by Toppr
Was this answer helpful?
0
Similar Questions
Q1
In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). Show that:
CM=12 AB
CM=12 AB
View Solution
Q2
In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). Show that:
∠DBC is a right angle.
∠DBC is a right angle.
View Solution
Q3
In the right triangle $ ABC$, right-angled at$ C$, $ M$ is the mid-point of the hypotenuse $ AB$.
$ C$ is joined to $ M $and produced to a point $ D $such that $ DM=CM$.
Point $ D $is joined to point $ B $(see Fig.). Show that:
View Solution
Q4
In right triangle ABC, right angled at C, M is the mid-point of hypotenuse AB. C is joined to M and produced to a point D such that DM = CM. Point D is joined to point B (see the given figure). What is the relation between CM and AB?
View Solution
Q5
In right triangle ABC, right angle is at C,M is the mid-point of hypotenuse AB,C is joined to M and produced to a point D such that DM=CM. Point D is joined to point B. Show that:
CM=12AB
CM=12AB
View Solution