In SHM the net force towards mean position is related to its displacement (x) from mean position by the relation

Question

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Answer 1

Simple harmonic motion is a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement.
$F = - k x$
$⟹ F \propto x$

Answer 2

Simple harmonic motion is a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement.

F = - k x

⟹ F \propto x

In SHM the net force towards mean position is related to its displacement (x) from mean position by the relation

$F \propto x$

$F \propto \frac{1}{x}$

$F \propto x^{2}$

$F \propto \frac{1}{x ^{2}}$

Simple harmonic motion is a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement.
$F = - k x$
$⟹ F \propto x$

Amplitude of oscillation of a particle that executes S.H.M. is 2 cm. Its displacement from its mean position in a time equal to 1/6th of its time period is

Assertion (A): The displacement time graph for a particle in SHM begins from mean position.
Reason (R): The displacement of a particle in SHM is given by y = A sin $ω t$

A man of mass 60 kg, standing on a platform, is executing SHM in a vertical plane. The displacement from mean position is $y = 0.5 s i n (2 π t)$ . The minimum value of frequency ( $f$ ) for which the man will feel weightlessness at the highest point is :

The maximum displacement of a particle executing SHM from its mean position is 2 cm and its time period is 1 s. The equation of its displacement will be

The acceleration (a) of SHM at mean position is :

Revise with Concepts

Force Law for SHM

In SHM the net force towards mean position is related to its displacement (x) from mean position by the relation

F∝x

F∝x1​

F∝x2

F∝x21​

Simple harmonic motion is a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement.F=−kx⟹F∝x

Amplitude of oscillation of a particle that executes S.H.M. is 2 cm. Its displacement from its mean position in a time equal to 1/6th of its time period is

Assertion (A): The displacement time graph for a particle in SHM begins from mean position. Reason (R): The displacement of a particle in SHM is given by y = A sin ωt

A man of mass 60 kg, standing on a platform, is executing SHM in a vertical plane. The displacement from mean position is y=0.5sin(2πt). The minimum value of frequency (f) for which the man will feel weightlessness at the highest point is :

The maximum displacement of a particle executing SHM from its mean position is 2 cm and its time period is 1 s. The equation of its displacement will be

The acceleration (a) of SHM at mean position is :

Revise with Concepts

Force Law for SHM

$F \propto x$

$F \propto \frac{1}{x}$

$F \propto x^{2}$

$F \propto \frac{1}{x ^{2}}$

Simple harmonic motion is a type of periodic motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacement.
$F = - k x$
$⟹ F \propto x$

Assertion (A): The displacement time graph for a particle in SHM begins from mean position.
Reason (R): The displacement of a particle in SHM is given by y = A sin $ω t$

A man of mass 60 kg, standing on a platform, is executing SHM in a vertical plane. The displacement from mean position is $y = 0.5 s i n (2 π t)$ . The minimum value of frequency ( $f$ ) for which the man will feel weightlessness at the highest point is :