In the above figure- a pair of parallel lines are by a transversal- Find the size of each lettered angle-

Question

Toppr Admin · Accepted Answer

In the given figure-Given angle is -60-0-x-60-0-160-160-160- -vertically opposite angles-But -angle y-angle x-160-160-160- -Corresponding angles-angle y-60-0-Hence- -angle x-60-0-angle y-60-0-

In the above figure, a pair of parallel lines are cut by a transversal. Find the size of each lettered angle.

In the given figure,
Given angle is $$60^{0}$$
$$x=60^{0}$$ (vertically opposite angles)
But $$\angle y=\angle x$$ (Corresponding angles)
$$\angle y=60^{0}$$
Hence, $$\angle x=60^{0},\angle y=60^{0}$$

In the above figure, a pair of parallel lines are cut by a transversal. Find the size of each lettered angle.

In the given figure,Given angle is $$60^{0}$$$$x=60^{0}$$ (vertically opposite angles)But $$\angle y=\angle x$$ (Corresponding angles)$$\angle y=60^{0}$$Hence, $$\angle x=60^{0},\angle y=60^{0}$$

In the given figure,
Given angle is $$60^{0}$$
$$x=60^{0}$$ (vertically opposite angles)
But $$\angle y=\angle x$$ (Corresponding angles)
$$\angle y=60^{0}$$
Hence, $$\angle x=60^{0},\angle y=60^{0}$$