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Question

In the adjacent figure, CD and BE are altitudes of an isosceles triangle ABC with AC=AB. Prove that AE=AD
1183797_03fbd1309d424f8d878d89a516fa8fd0.png

Solution
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Given DC and BE are altitude and AB=AC
So Here CDB=CDA=90 --------------- (1)
AndBEC=BEA=90 --------------- (2)
So from equation (1) and (2)
we can say
CDB=BEC90 --------------- (3)
And As given ABC is a isosceles triangle so , from base angle theorem,
we can say that
ABC=ACB ---------- (4)
Now In CBD and BCE
CDB=BEC ( From equation (3)
DBC=ECB ( As ABC=DBC) ( same angles )
And ACB=ECB( same angles )
And from equation (4) we know ABC=ACB
And BC=BC ( Common side )
Hence,CBD is congruent to BCE ( By AAS rule )
So,AE=AD ( By CPCT rule ) ( Hence proved )

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