In the adjacent figure, if ∠AOC=1100, then the value of ∠Dand∠B respectively.
550,1250
550,1100
1100,250
1250,550
A
550,1100
B
550,1250
C
1100,250
D
1250,550
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Solution
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Given, ∠AOC=1100 Also, we know ∠AOC=2∠ADC (angle subtended by an arc at the center is double the angle subtended by it at any point on the circumference) ∴∠ADC=550
Also, ∠B+∠D=1800 (ABCD is a cyclic quadrilateral and opposite angles of it are supplementary) ⟹∠B=1250
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