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Question

# In the adjoining diagram R1=10Ω,R2=20Ω,R3=40Ω,R4=80Ω and VA=5 V,VB=10 V,VC=20V,VD=15 V. The current in the resistance R1 will be0.4 A towards O0.4 A away from O0.6 A towards O0.6 A away from O

A
0.6 A towards O
B
0.6 A away from O
C
0.4 A towards O
D
0.4 A away from O
Solution
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#### Let the potential at the common point of all branches be V.Then, using nodal analysis:5−V10=V−1020+V−2040+V−1580V=13515,I=5−V10=−0.4 ASince, negative sign is there, that means the current will be away from O.

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Q2

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