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In the adjoining figure abcd is a square and edc is an equilateral triangle

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Similar Questions
Q1

In the adjoining figure, ABCD is a square and EDC is an equilateral triangle. Prove that
AE=BE.


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Q2
In the adjoining figure, ABCD is a square and EDC is an equilateral triangle. Prove that
DAE=15o.
1063520_ebb94cb6460e4bca9d53ad57bf69dfb7.jpg
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Q3

In the adjoining figure, ABCD is a square and ΔEDC is an equilateral triangle. Prove that

(i) AE = BE, (ii) DAE=15.

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Q4

In the adjoining figure ABCD is a rhombus and EDC is an equilateral triangle. If DAB = 480, find BFC.


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Q5
In the adjoining figure, ABCD is a rhombus and EDC is an equilateral triangle. If DAB=48o , find
i) BEC
ii) DEB
iii) BFC
1036858_2a1849b055a041f193e5cf794aebefb1.PNG
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