In the adjoining figure- OACB is a quadrant of a circle of radius 7-cm- The perimeter of the quadrant isNote- pi - dfrac-22-7-25- cm11- cm18- cm36- cm

Question

Toppr Admin · Accepted Answer

Perimeter -14-xD7-2-x3C0-r-2r-12-xD7-227-xD7-7-2-xD7-7-cm-25cm

In the adjoining figure, $O A C B$ is a quadrant of a circle of radius $7 c m$ . The perimeter of the quadrant is
Note: $π = \frac{22}{7}$

$25 c m$
$11 c m$
$18 c m$
$36 c m$

Perimeter $= \frac{1}{4} \times 2 π r + 2 r = (\frac{1}{2} \times \frac{22}{7} \times 7 + 2 \times 7) c m$
$= 25 c m$

In the adjoining figure, OACB is a quadrant of a circle of radius 7cm. The perimeter of the quadrant isNote: π=22725cm11cm18cm36cm

Perimeter =14×2πr+2r=(12×227×7+2×7)cm=25cm

In the adjoining figure, $O A C B$ is a quadrant of a circle of radius $7 c m$ . The perimeter of the quadrant is
Note: $π = \frac{22}{7}$

$25 c m$
$11 c m$
$18 c m$
$36 c m$

Perimeter $= \frac{1}{4} \times 2 π r + 2 r = (\frac{1}{2} \times \frac{22}{7} \times 7 + 2 \times 7) c m$
$= 25 c m$