In the of Huygens eyepiece- the ratio of focal length of eye lens- effective focal length and length of the eyepiece is -1 - 2 - 32 - 3 - 42 - 1 - 33 - 2 - 4

Question

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For Huygens eyepiece-Focal length of eye lens - fEffective focal length - 3f2Length of eye piece - 2fSo ratio-xA0-of-xA0-focal length of eye lens- effective focal length-xA0-and length of the eyepiece is -f - 3f2- 2f-2-3-4-xA0-Answer- B- 2-3-4

In the case of Huygens eyepiece, the ratio of focal length of eye lens, effective focal length and length of the eyepiece is :
1 : 2 : 3
2 : 3 : 4
2 : 1 : 3
3 : 2 : 4

For Huygens eyepiece:

Focal length of eye lens = $f$

Effective focal length = $\frac{3 f}{2}$

Length of eye piece = $2 f$

So ratio of focal length of eye lens, effective focal length and length of the eyepiece is $= f$ : $\frac{3 f}{2}$ : $2 f = 2 : 3 : 4$

Answer. B) 2:3:4

In the case of Huygens eyepiece, the ratio of focal length of eye lens, effective focal length and length of the eyepiece is :1 : 2 : 32 : 3 : 42 : 1 : 33 : 2 : 4

For Huygens eyepiece:Focal length of eye lens = fEffective focal length = 3f2Length of eye piece = 2fSo ratio of focal length of eye lens, effective focal length and length of the eyepiece is =f : 3f2: 2f=2:3:4 Answer. B) 2:3:4

In the case of Huygens eyepiece, the ratio of focal length of eye lens, effective focal length and length of the eyepiece is :
1 : 2 : 3
2 : 3 : 4
2 : 1 : 3
3 : 2 : 4

For Huygens eyepiece:

Focal length of eye lens = $f$

Effective focal length = $\frac{3 f}{2}$

Length of eye piece = $2 f$

So ratio of focal length of eye lens, effective focal length and length of the eyepiece is $= f$ : $\frac{3 f}{2}$ : $2 f = 2 : 3 : 4$

Answer. B) 2:3:4