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Question

In the chemical reaction N2+3H22NH3 at equilibruim:
  1. the reaction has stopped
  2. equal volumes of N2 & H2 are reacting
  3. equal masses of N2 & H2 are reacting
  4. the same amount of ammonia is formed as is decomposed into N2 and H2

A
the reaction has stopped
B
equal volumes of N2 & H2 are reacting
C
the same amount of ammonia is formed as is decomposed into N2 and H2
D
equal masses of N2 & H2 are reacting
Solution
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At equilibrium the amount of products formed i.e. formation of products is same as the amount of reactants decomposed at this point.

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Q1
In the chemical reaction,
N2(g)+3H2(g)2NH3(g)
at equilibrium point:
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Q2
In the reaction N2+3H22NH3, the ratio by volume of N2, H2 andNH3 is 1:3:2.

This illustrates the law of:

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Q3
In a reaction N2+3H22NH3, 40 ml of each N2 and H2 are taken to react together so that 25% yield of NH3 was obtained. The volume of N2 present in the container is?
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Q4
For the reaction,N2+3H22NH3, the equilibrium expression may be written as:
K=[NH3]2[N2][H2]3.

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Q5
For the reaction N2+3H22NH3, the equilibrium expression may be written as K[NH3]2[N2][H2]3.

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