In the circuit shown- a meter bridge is in its balanced state- The meter bridge wire has a resistance 0-1 ohm-cm- The value of unknown resistance X and the current drawn from the battery of negligible resistance is10 Omega- 0-1A4 Omega- 1-0A12 Omega- 0-5A6 Omega- 5A

Question

Toppr Admin · Accepted Answer

Resistance of the part ACRAC-0-1-xD7-40-4-x3A9- and RCB-0-1-xD7-60-6-x3A9-In balanced condition X6-46-x21D2-X-4-x3A9-Equivalent resistance Req-5-x3A9- so current drawn from battery i-55-1-xA0-A

In the circuit shown, a meter bridge is in its balanced state. The meter bridge wire has a resistance 0.1 ohm/cm. The value of unknown resistance X and the current drawn from the battery of negligible resistance is

$10 Ω, 0.1 A$
$4 Ω, 1.0 A$
$12 Ω, 0.5 A$
$6 Ω, 5 A$

Resistance of the part $A C$
$R_{A C} = 0.1 \times 40 = 4 Ω$ and $R_{C B} = 0.1 \times 60 = 6 Ω$
In balanced condition $\frac{X}{6} = \frac{4}{6} \Rightarrow X = 4 Ω$
Equivalent resistance $R_{e q} = 5 Ω$ so current drawn from battery $i = \frac{5}{5} = 1 A$

In the circuit shown, a meter bridge is in its balanced state. The meter bridge wire has a resistance 0.1 ohm/cm. The value of unknown resistance X and the current drawn from the battery of negligible resistance is10Ω,0.1A4Ω,1.0A12Ω,0.5A6Ω,5A

Resistance of the part ACRAC=0.1×40=4Ω and RCB=0.1×60=6ΩIn balanced condition X6=46⇒X=4ΩEquivalent resistance Req=5Ω so current drawn from battery i=55=1 A

In the circuit shown, a meter bridge is in its balanced state. The meter bridge wire has a resistance 0.1 ohm/cm. The value of unknown resistance X and the current drawn from the battery of negligible resistance is

$10 Ω, 0.1 A$
$4 Ω, 1.0 A$
$12 Ω, 0.5 A$
$6 Ω, 5 A$

Resistance of the part $A C$
$R_{A C} = 0.1 \times 40 = 4 Ω$ and $R_{C B} = 0.1 \times 60 = 6 Ω$
In balanced condition $\frac{X}{6} = \frac{4}{6} \Rightarrow X = 4 Ω$
Equivalent resistance $R_{e q} = 5 Ω$ so current drawn from battery $i = \frac{5}{5} = 1 A$