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In the circuit shown in figure E1 = 7V,
Question
In the circuit shown in figure
E
1
= 7V,
E
2
=
7
V
R
1
=
R
2
=
1
Ω
and
R
3
=
3
respectively. The current through the resistance
R
3
is:
A
2A
B
3.5A
C
1.75A
D
none of these
Hard
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Updated on : 2022-09-05
Solution
Verified by Toppr
Correct option is A)
Using Kirchoff's loop law in loop BCFAB-
i
1
R
1
+
(
i
1
+
i
2
)
R
3
=
E
1
⟹
i
1
+
3
(
i
1
+
i
2
)
=
7
⟹
4
i
1
+
3
i
2
=
7
Now, applying Kirchoff's loop law in loop BCDEFAB-
i
1
R
1
−
i
2
R
2
+
E
2
=
E
1
⟹
i
1
−
i
2
+
7
=
7
⟹
i
1
=
i
2
Hence, in equation-
4
i
1
+
3
i
2
=
7
⟹
4
i
1
+
3
i
1
=
7
⟹
i
1
=
1
A
and
i
2
=
i
1
=
1
A
Current through
R
3
is
i
1
+
i
2
=
2
A
Answer-(A)
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