In the diagram shownmu -1-mu mu -1-mu

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In the diagram shown

$μ^{1} = μ$
$μ^{1} < μ$
$μ^{1} \geq μ$
$μ^{1} > μ$

μ^{1} = μ

μ^{1} > μ

μ^{1} \geq μ

μ^{1} < μ

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Solution

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Since, the given lens is a convex lens hence it should converge a parallel beam of light falling on it to a single focal point. However, since it is showing the exactly opposite behaviour, thus it is definitely placed in a medium of higher refractive index.
Thus, we conclude that $μ_{1} > μ$

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In the diagram shownμ1=μμ1<μμ1≥μμ1>μ

Since, the given lens is a convex lens hence it should converge a parallel beam of light falling on it to a single focal point. However, since it is showing the exactly opposite behaviour, thus it is definitely placed in a medium of higher refractive index.Thus, we conclude that μ1>μ

In the diagram shown

$μ^{1} = μ$
$μ^{1} < μ$
$μ^{1} \geq μ$
$μ^{1} > μ$

Since, the given lens is a convex lens hence it should converge a parallel beam of light falling on it to a single focal point. However, since it is showing the exactly opposite behaviour, thus it is definitely placed in a medium of higher refractive index.
Thus, we conclude that $μ_{1} > μ$