In the diagram shown

Question

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Answer 1

Since, the given lens is a convex lens hence it should converge a parallel beam of light falling on it to a single focal point. However, since it is showing the exactly opposite behaviour, thus it is definitely placed in a medium of higher refractive index.
Thus, we conclude that $μ_{1} > μ$

Answer 2

Since, the given lens is a convex lens hence it should converge a parallel beam of light falling on it to a single focal point. However, since it is showing the exactly opposite behaviour, thus it is definitely placed in a medium of higher refractive index.
Thus, we conclude that

μ_{1} > μ

In the diagram shown

$μ^{1} = μ$

$μ^{1} < μ$

$μ^{1} > μ$

$μ^{1} \geq μ$

Since, the given lens is a convex lens hence it should converge a parallel beam of light falling on it to a single focal point. However, since it is showing the exactly opposite behaviour, thus it is definitely placed in a medium of higher refractive index.
Thus, we conclude that $μ_{1} > μ$

The following spherical lenses not exhibiting dispersion is
(The radii of curvature of the surface of the lenses are as given in the diagrams)

Look at the ray diagram shown, what will be the focal length of the 1st and the 2nd lens, if the incident light ray passes without any deviation?

The diagram shows a concavo-convex lens $μ_{2}$ . What is the condition on the refractive indices so that the lens is diverging?

Consider the ray shown in the diagram as paraxial. The image of the virtual point object $O$ formed by the lens $L L$ is

The refractive index of the material of a concave lens is $μ$ and is placed in the medium of refractive index $μ^{1}$ . If $μ^{1} < μ$ the following ray diagram is correct

Revise with Concepts

Calculation of Focal Length for Combination of Mirror and Lens

Object and Lens Placed in Water

Problems in Lenses and Mirrors - Problem L1

In the diagram shown

μ1=μ

μ1<μ

μ1>μ

μ1≥μ

Since, the given lens is a convex lens hence it should converge a parallel beam of light falling on it to a single focal point. However, since it is showing the exactly opposite behaviour, thus it is definitely placed in a medium of higher refractive index. Thus, we conclude that μ1​>μ

The following spherical lenses not exhibiting dispersion is (The radii of curvature of the surface of the lenses are as given in the diagrams)

Look at the ray diagram shown, what will be the focal length of the 1st and the 2nd lens, if the incident light ray passes without any deviation?

The diagram shows a concavo-convex lens μ2​. What is the condition on the refractive indices so that the lens is diverging?

Consider the ray shown in the diagram as paraxial. The image of the virtual point object O formed by the lens LL is

The refractive index of the material of a concave lens is μ and is placed in the medium of refractive index μ1 . If μ1<μ the following ray diagram is correct

Revise with Concepts

Calculation of Focal Length for Combination of Mirror and Lens

Object and Lens Placed in Water

Problems in Lenses and Mirrors - Problem L1

$μ^{1} = μ$

$μ^{1} < μ$

$μ^{1} > μ$

$μ^{1} \geq μ$

Since, the given lens is a convex lens hence it should converge a parallel beam of light falling on it to a single focal point. However, since it is showing the exactly opposite behaviour, thus it is definitely placed in a medium of higher refractive index.
Thus, we conclude that $μ_{1} > μ$

The following spherical lenses not exhibiting dispersion is
(The radii of curvature of the surface of the lenses are as given in the diagrams)

The diagram shows a concavo-convex lens $μ_{2}$ . What is the condition on the refractive indices so that the lens is diverging?

Consider the ray shown in the diagram as paraxial. The image of the virtual point object $O$ formed by the lens $L L$ is

The refractive index of the material of a concave lens is $μ$ and is placed in the medium of refractive index $μ^{1}$ . If $μ^{1} < μ$ the following ray diagram is correct