If coordinates of P,Q, and R are (3,6),(-1,3) and (2,-1) respectively. Then area of △PQR is ____ square units.
12
12.5
14
13
A
12.5
B
13
C
12
D
14
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Solution
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The correct option is B 12.5
Area of triangle having vertices (x1,y1),(x2,y2) and (x3,y3) is given by =12×[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)]
Area of ΔPQR is given by =12[3(3+1)−1(−1−6)+2(6−3)] =12(12+7+6)=12.5 square units.
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