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Question

In the electrochemical cell shown above, which of the following half-reactions occurs at the anode?
524234.JPG
  1. Cu2++eCu
  2. Zn(s)Zn2++2e
  3. Zn2++2eZn(s)
  4. Cu(s)Cu2++2e
  5. Cu2++2eCu(s)

A
Zn2++2eZn(s)
B
Cu2++eCu
C
Zn(s)Zn2++2e
D
Cu2++2eCu(s)
E
Cu(s)Cu2++2e
Solution
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At anode, oxidation will take place and Zn(s) will get oxidised to Zn2+ leaving negatively charged electrons, making anode negatively charged, repelling negatively charged NO3.

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Similar Questions
Q1
The standard reduction potential E, for the half reaction are:-
ZnZn2++2e;E=0.76 V
CuCu2++2e;E=0.34 V
The emf for the cell reaction, Zn(s)+Cu2+Zn2++Cu(s) is_____________.
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Q2

The cell representation of the given reaction is:
Zn(s) + Cu2+ → Zn2+ + Cu(s)


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Q3
A cell is represented by
ZnZn2+(aq)Cu2+(aq)Cu.
Given, Cu2++2eCu,E=+0.35V and Zn2++2eZn,E=0.763V. Write the cell reactions, emf of the cell and state whether the cell reaction will be spontaneous or not?
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Q4
Which of the following statement(s) is/are true?

Zn2+(aq)+2eZn(s); E0=0.76 V
Cu2+(aq)+2eCu(s); E0=0.34 V
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Q5
CuI(s)+eCu(s)+I;EoCu+/Cu=0.16V
Zn2+(aq)+2eZn(s); EoZn2+/Zn=0.76V

Calculate the EMF.

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