In the figure- given below- AB - AC -Hence- angle BAC - angle ACD -TrueFalse

Question

In the figure- given below-  AB - AC -Hence-  angle BAC - angle ACD -TrueFalse

Toppr Admin · Accepted Answer

Given- AB-AC-Hence- -x2220-ABC-x2220-ACB -Isosceles triangle property-Also- OB bisects -x2220-B and OC bisects -x2220-C-Thus- -x2220-OBC-x2220-ABO-12-x2220-B-and -x2220-OCB-x2220-ACO-12-x2220-C-

In the figure, given below, $A B = A C$ .
Hence, $∠ B A C = ∠ A C D$ .

True
False

Given, $A B = A C$ .
Hence, $∠ A B C = ∠ A C B$ (Isosceles triangle property).
Also, $O B$ bisects $∠ B$ and $O C$ bisects $∠ C$ .
Thus, $∠ O B C = ∠ A B O = \frac{1}{2} (∠ B)$
and $∠ O C B = ∠ A C O = \frac{1}{2} (∠ C)$ .

In the figure, given below, AB=AC.Hence, ∠BAC=∠ACD.TrueFalse

Given, AB=AC.Hence, ∠ABC=∠ACB (Isosceles triangle property).Also, OB bisects ∠B and OC bisects ∠C.Thus, ∠OBC=∠ABO=12(∠B)and ∠OCB=∠ACO=12(∠C).

In the figure, given below, $A B = A C$ .
Hence, $∠ B A C = ∠ A C D$ .

True
False

Given, $A B = A C$ .
Hence, $∠ A B C = ∠ A C B$ (Isosceles triangle property).
Also, $O B$ bisects $∠ B$ and $O C$ bisects $∠ C$ .
Thus, $∠ O B C = ∠ A B O = \frac{1}{2} (∠ B)$
and $∠ O C B = ∠ A C O = \frac{1}{2} (∠ C)$ .