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Question

In the figure given below, Find the
equivalent capacitance of the network between points A and B
Given : $$C_1 = C_5 = 4 \mu F , C_2 = C_3 = C_4 = 2 \mu F$$.

Solution
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Given circuit,
$$(C_1 = C_5 = 4 \mu F , C_2 = C_3 = C_4 = 2 \mu F)$$
Ref. image
from about circuit diagram $$C_1 \, \& \, C_2$$ and $$C_4 \,\& \, C_5$$ are shorted with wire. So total potential drop to move from $$C_1 $$ to $$C_2$$ and $$C_4$$ to $$C_5$$ will be zero

$$\therefore C_{eq} = C_3 = 2 \mu F$$

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