In the figure given below- displaystyle Delta BCAcong Delta BCD- Corresponding angle to displaystyle angle D is -displaystyle angle Bdisplaystyle angle Cdisplaystyle angle Ddisplaystyle angle A

Question

Toppr Admin · Accepted Answer

Given-x25B3-BCA-x2245-x25B3-BCD-Then-the corresponding parts will also be equal-That-is by CPCT rule- corresponding parts of congruent triangles are equal-Then-BC-BC-xA0- CA-CD- BA-BD- -x2220-B-x2220-B-xA0-x2220-C-x2220-C and-xA0-x2220-A-x2220-D-

In the figure given below, $Δ B C A ≅ Δ B C D$ . Corresponding angle to $∠ D$ is ...........

$∠ B$
$∠ C$
$∠ D$
$∠ A$

Given $△ B C A ≅ △ B C D$ .

Then the corresponding parts will also be equal.

That is by CPCT rule, corresponding parts of congruent triangles are equal.

Then, $B C = B C$ , $C A = C D$ , $B A = B D$ , $∠ B = ∠ B$ , $∠ C = ∠ C$ and $∠ A = ∠ D$ .

In the figure given below, ΔBCA≅ΔBCD. Corresponding angle to ∠D is ...........∠B∠C∠D∠A

Given △BCA≅△BCD. Then the corresponding parts will also be equal. That is by CPCT rule, corresponding parts of congruent triangles are equal. Then, BC=BC, CA=CD, BA=BD, ∠B=∠B, ∠C=∠C and ∠A=∠D.

In the figure given below, $Δ B C A ≅ Δ B C D$ . Corresponding angle to $∠ D$ is ...........

$∠ B$
$∠ C$
$∠ D$
$∠ A$

Given $△ B C A ≅ △ B C D$ .

Then the corresponding parts will also be equal.

That is by CPCT rule, corresponding parts of congruent triangles are equal.

Then, $B C = B C$ , $C A = C D$ , $B A = B D$ , $∠ B = ∠ B$ , $∠ C = ∠ C$ and $∠ A = ∠ D$ .