Question

In the figure, $l||m$ and $n||p$. If $\angle 1={60}^{\circ }$, then $\angle 2=3\times \angle 1$.

• A. True
• B. False

Answer 1

Answer: (B)

Given, $\angle 1={60}^{\circ }$

$\angle 1=\angle 3={60}^{\circ }$ ------(corresponding angles)

$\angle 2+\angle 3={180}^{\circ }$ ------(sum of adjacent angles in a parallelogram is ${180}^{\circ }$)

${60}^{\circ }+\angle 2={180}^{\circ }$

$\angle 2={180}^{\circ }-{60}^{\circ }={120}^{\circ }$

$\therefore \angle 2=2\times \angle 1$