In the figure shown here- BDEC is a rectangle- ABC and DEF are straight lines- The area- in cm-2 - of the whole figure is - -120128136142

Question

Toppr Admin · Accepted Answer

-xA0-Area-xA0-of the whole figure-xA0-area-xA0-of rectangle BDEC-xA0-area-xA0-of triangle ABD-xA0-area-xA0-of-xA0-triangle ECF-DE-xD7-EC-12-xD7-AB-xD7-BD-12-xD7-CE-xD7-EF-8-xD7-10-12-xD7-8-xD7-3-12-xD7-8-xD7-11-80-12-44-136cm2

In the figure shown here, $B D E C$ is a rectangle. $A B C$ and $D E F$ are straight lines. The area, in cm $^{2}$ , of the whole figure is ______ .

$120$
$128$
$136$
$142$

Area of the whole figure= area of rectangle BDEC+ area of triangle ABD+ area of triangle ECF
$= D E \times E C + \frac{1}{2} \times A B \times B D + \frac{1}{2} \times C E \times E F$
$= 8 \times 10 + \frac{1}{2} \times 8 \times 3 + \frac{1}{2} \times 8 \times 11$
$= 80 + 12 + 44$
$= 136 {c m}^{2}$

In the figure shown here, BDEC is a rectangle. ABC and DEF are straight lines. The area, in cm2 , of the whole figure is ______ .120128136142

Area of the whole figure= area of rectangle BDEC+ area of triangle ABD+ area of triangle ECF=DE×EC+12×AB×BD+12×CE×EF=8×10+12×8×3+12×8×11=80+12+44=136cm2

In the figure shown here, $B D E C$ is a rectangle. $A B C$ and $D E F$ are straight lines. The area, in cm $^{2}$ , of the whole figure is ______ .

$120$
$128$
$136$
$142$

Area of the whole figure= area of rectangle BDEC+ area of triangle ABD+ area of triangle ECF
$= D E \times E C + \frac{1}{2} \times A B \times B D + \frac{1}{2} \times C E \times E F$
$= 8 \times 10 + \frac{1}{2} \times 8 \times 3 + \frac{1}{2} \times 8 \times 11$
$= 80 + 12 + 44$
$= 136 {c m}^{2}$