Question

In the figure shown the angle made by the light ray with the normal in the medium of refractive index $\sqrt{2}$ is

• A. ${60}^o$
• B. ${90}^o$
• C. ${30}^o$
• D. None of these

Answer 1

Answer: (C)

Given: ${\theta }_1={45}^o$

Using Snell's law of refraction : $n_1\times sin{\theta }_1=n_3\times sin{\theta }_3$

$\therefore$ $1\times sin{45}^o=\sqrt{2}\times sin{\theta }_3$

OR $sin{\theta }_3=\frac{1}{\sqrt{2}}\times \frac{1}{\sqrt{2}}=\frac{1}{2}$

$⟹{\theta }_3={30}^o$