In the five digit number 1b6a3, a is the greatest single digit perfect cube and twice of it exceeds by 7. Then the sum of the number and its cube root is __________.
18700
19710
11862
25320
A
18700
B
11862
C
19710
D
25320
Open in App
Solution
Verified by Toppr
5 digit no. is =1b6a3 Greatest single digit perfect cube=8 ∴a=8 Given b=2a−7=2×8−7=9 No: 19683 Ans:19683+3√19683=19683+27 =19710
Was this answer helpful?
22
Similar Questions
Q1
In the five digit number 1b6a3, a is the greatest single digit perfect cube and twice of it exceeds by 7. Then the sum of the number and its cube root is __________.
View Solution
Q2
In a five-digit number 2x7xy, x is the greatest single digit perfect square and y is the smallest single digit perfect cube. The sum of the number and its cube root is
पाँच अंकों वाली एक संख्या 2x7xy में, x महत्तम एक अंक वाला पूर्ण वर्ग है तथा y लघुत्तम एक अंक वाला पूर्ण घन है। तब संख्या तथा इसके घनमूल का योगफल है
View Solution
Q3
If the difference between the smallest five digit perfect cube and the greatest four digit perfect cube is a then(a - 56) can be a cube of
View Solution
Q4
State true or false.
(i) Cube of any odd number is even.
(ii) A perfect cube does not end with two zeroes.
(iii) If square of a number ends with 5, then its cube ends with
25.
(iv) There is no perfect cube which ends with 8.
(v) The cube of a two digit number may be a three digit number.
(vi) The cube of a two digit number may have seven or more digits.
(vii) The cube of a single digit number may be a single digit
number.
View Solution
Q5
The product of the digits of a two digit number is 24. If its units's digit exceeds twice its ten's digit by 2; find the number.