In the following figure PT is of length 8 cm. OP is 10 cm. Then the radius of the circle is _______.
2 cm
18 cm
1 cm
6 cm
A
1 cm
B
6 cm
C
2 cm
D
18 cm
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Solution
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Radius dropped on any tangent to a circle touches the circle at 90∘
⇒OP2=OT2+PT2
⇒100=64+OT2
∴OT=6 cm
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Similar Questions
Q1
In the following figure PT is of length 8 cm. OP is 10 cm. Then the radius of the circle is _______.
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Q2
In the given figure, PT is a tangent to a circle with centre O. If OT = 6 cm and OP = 10 cm, then the length of tangent PT is
(a) 8 cm
(b) 10 cm
(c) 12 cm
(d) 16 cm