In the following, find the co-ordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation :
3−2x=7;2y+1=10−212y.
(−2,2)
(−4,2)
(−2,−2)
(−4,−2)
A
(−2,2)
B
(−2,−2)
C
(−4,2)
D
(−4,−2)
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Solution
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First equation: 3−2x=7 =>2x=3−7=−4 =>x=−2
Second equation: 2y+1=10−212y
=>2y+1=10−52y
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