Question

In the following sequence of reactions,


CH3BrKCNAH3O+BLiAlH4C

The end product C is:

A
Ethyl alcohol
B
Acetaldehyde
C
Acetone
D
Methane
Solution
Verified by Toppr

The end product C is ethyl alcohol.
CH3BrKCNCH3CNAH3O+CH3COOHBLiAlH4CH3CH2OHC
Methyl bromide reacts with KCN to form acetonitrile. Br atom is replaced with CN group. Hydrolysis of cyano group gives carboxylic group. Reduction of carboxylic group gives hydroxyl group.

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