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Question

In the following table, given that a is the first term, d the common difference and an the nth term of the AP.
adnan
(i)738.......
(ii)-18.......100
(iii).......-318-5
(iv)-18.92.5.......3.6
(v)3.50105.......

  1. (i)an=13(ii)d=1(iii)a=46(iv)n=9(v)an=3.5
  2. (i)an=36(ii)d=7(iii)a=46(iv)n=13(v)an=3.5
  3. (i)an=28(ii)d=2(iii)a=46(iv)n=10(v)an=3.5
  4. (i)an=18(ii)d=3(iii)a=46(iv)n=4(v)an=3.5

A
(i)an=36(ii)d=7(iii)a=46(iv)n=13(v)an=3.5
B
(i)an=18(ii)d=3(iii)a=46(iv)n=4(v)an=3.5
C
(i)an=13(ii)d=1(iii)a=46(iv)n=9(v)an=3.5
D
(i)an=28(ii)d=2(iii)a=46(iv)n=10(v)an=3.5
Solution
Verified by Toppr

Here we use the formula tn=a+(n1)d

(i). a8=a+(81)d=7+73=28
(ii). a=18,d=?
tn=1+(n1)d
0=18+(101)d
d=2
(iii). 5=a+(181)(3)
Solve this to get a=46.
(iv). 3.6=18.9+(n1)2.5
n= 10.
(v). tn=3.5+(1051)0=3.5

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Similar Questions
Q1
In the following table, given that a is the first term, d the common difference and an the nth term of the AP.
adnan
(i)738.......
(ii)-18.......100
(iii).......-318-5
(iv)-18.92.5.......3.6
(v)3.50105.......

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