In the formula x- 3yz - 2 - x and z have dimensions of capacitance and magnetic induction field strength respectively- The dimensions of y in system is - M - -3 - L - -2 - T - 4 - Q - 4 - M - -2 - L - -2 - T - 2 - Q - 2 - M - -3 - L - -1 - T - 4 - Q - 4 - M - 2 - L - 2 - T - -3 - Q - -1 -

Question

Toppr Admin · Accepted Answer

X-3yz2x-M-x2212-1L-x2212-2I2T4z-M1I-x2212-1T-x2212-2Let- y-M-x3B1-L-x3B2-T-x3B3-Q-x3B4-M-x2212-1L-x2212-2I2T4-M-x3B1-L-x3B2-T-x3B3-Q-x3B4-M-1L0I-x2212-1T-x2212-2-IT-Q-x3B1-x2212-3-x3B2-x2212-2-x3B3-4-x3B4-4y-M-x2212-3L-x2212-2T4Q4

In the formula $x = {3 y z}^{2}$ , $x$ and $z$ have dimensions of capacitance and magnetic induction field strength respectively. The dimensions of $y$ in system is :
$M^{- 3} L^{- 2} T^{4} Q^{4}$
$M^{- 2} L^{- 2} T^{2} Q^{2}$
$M^{- 3} L^{- 1} T^{4} Q^{4}$
$M^{2} L^{2} T^{- 3} Q^{- 1}$

$x = 3 y z^{2}$
$x = M^{- 1} L^{- 2} I^{2} T^{4}$
$z = M^{1} I^{- 1} T^{- 2}$
Let, $y = M^{α} L^{β} T^{γ} Q^{δ}$
$(M^{- 1} L^{- 2} I^{2} T^{4}) = (M^{α} L^{β} T^{γ} Q^{δ}) (M^{+ 1} L^{0} I^{- 1} T^{- 2})$
$I T = Q$
$α = - 3, β = - 2, γ = 4, δ = 4$
$y = M^{- 3} L^{- 2} T^{4} Q^{4}$

In the formula x=3yz2, x and z have dimensions of capacitance and magnetic induction field strength respectively. The dimensions of y in system is :M−3L−2T4Q4M−2L−2T2Q2M−3L−1T4Q4M2L2T−3Q−1

x=3yz2x=M−1L−2I2T4z=M1I−1T−2Let, y=MαLβTγQδ(M−1L−2I2T4)=(MαLβTγQδ)(M+1L0I−1T−2)IT=Qα=−3,β=−2,γ=4,δ=4y=M−3L−2T4Q4

In the formula $x = {3 y z}^{2}$ , $x$ and $z$ have dimensions of capacitance and magnetic induction field strength respectively. The dimensions of $y$ in system is :
$M^{- 3} L^{- 2} T^{4} Q^{4}$
$M^{- 2} L^{- 2} T^{2} Q^{2}$
$M^{- 3} L^{- 1} T^{4} Q^{4}$
$M^{2} L^{2} T^{- 3} Q^{- 1}$

$x = 3 y z^{2}$
$x = M^{- 1} L^{- 2} I^{2} T^{4}$
$z = M^{1} I^{- 1} T^{- 2}$
Let, $y = M^{α} L^{β} T^{γ} Q^{δ}$
$(M^{- 1} L^{- 2} I^{2} T^{4}) = (M^{α} L^{β} T^{γ} Q^{δ}) (M^{+ 1} L^{0} I^{- 1} T^{- 2})$
$I T = Q$
$α = - 3, β = - 2, γ = 4, δ = 4$
$y = M^{- 3} L^{- 2} T^{4} Q^{4}$