In the expansion of an Ideal gas- its internal energyremains constantdecreasesincreasessometimes increases - sometimes decreases

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Toppr Admin · Accepted Answer

In free expansion - air is expanded against vacuum- Therefore work done is zero- -xA0-Also the supplied heat is zero-dQ - 0- dW - 0Therefore by First-xA0-Law-xA0-of-xA0-Thermodynamics- dQ-dU-dW -xA0-change in internal energy is also zero-

In the free expansion of an Ideal gas, its internal energy
remains constant
decreases
increases
sometimes increases , sometimes decreases

In free expansion , air is expanded against vacuum. Therefore work done is zero. Also the supplied heat is zero.

dQ = 0, dW = 0

Therefore by $F i r s t L a w o f T h e r m o d y n a m i c s$ , $d Q = d U + d W$ change in internal energy is also zero.

In the free expansion of an Ideal gas, its internal energyremains constantdecreasesincreasessometimes increases , sometimes decreases

In free expansion , air is expanded against vacuum. Therefore work done is zero. Also the supplied heat is zero.dQ = 0, dW = 0Therefore by First Law of Thermodynamics, dQ=dU+dW change in internal energy is also zero.

In the free expansion of an Ideal gas, its internal energy
remains constant
decreases
increases
sometimes increases , sometimes decreases

In free expansion , air is expanded against vacuum. Therefore work done is zero. Also the supplied heat is zero.

dQ = 0, dW = 0

Therefore by $F i r s t L a w o f T h e r m o d y n a m i c s$ , $d Q = d U + d W$ change in internal energy is also zero.