In the given circle ABCD- O is the centre and angle BDC - 42-o- The angleACB is equal to42-o45-o48-o60-o

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In the given circle ABCD, O is the centre and $∠ B D C = 42^{o}$ . The $∠$ ACB is equal to

42 $^{o}$
45 $^{o}$
48 $^{o}$
60 $^{o}$

^{o}

^{o}

^{o}

^{o}

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