In the given circuit, the charge on $$4 \mu F$$ capacitor will be :
A
$$13.4 \, \mu C$$
B
$$9.6 \, \mu C$$
C
$$5.4 \, \mu C$$
D
$$24 \, \mu C$$
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Solution
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Correct option is B. $$24 \, \mu C$$ So total charge flow $$= q = 5.4 \,\mu F \times 10V$$ $$= 54 \,\mu C$$ The charge will be distributed in the ratio of capacitance $$\Rightarrow \dfrac{q_1}{q_2} = \dfrac{2.4}{3} = \dfrac{4}{5}$$ $$\therefore 9X = 54\mu C \Rightarrow X = 6\mu C$$ $$\therefore$$ Charge on $$4 \mu F$$ capacitor will be $$= 4X = 4 \times 6\mu C$$ $$= 24 \mu C$$
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