Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Kirchoff's Voltage Law

Question

In the given circuit, the potential difference across $3 μ F$ capacitor will be:

$12 V$
$6 V$
$10 V$
$4 V$

A

4 V

B

12 V

C

10 V

D

6 V

Open in App

Solution

Verified by Toppr

both capacitor and battery are in series so

$V_{e q} = 20 - 4 = 16 v$

$C_{e} q = \frac{3 \times 5}{5 + 3} = \frac{15}{8}$

$q = C_{e q} \times V_{e q} = \frac{15}{8} \times 16 = 30$

$V_{3} = \frac{q}{c} = \frac{30}{3} = 10 v$

Was this answer helpful?

18

Similar Questions

Q1

In the given circuit, the potential difference across

3 μ F

capacitor will be:

View Solution

Q2

Three capacitors,

3 μ F, 6 μ F

and

6 μ F

are connected in series to a source of 120V. The potential difference, in volts, across the

3 μ F

capacitor will be

View Solution

Q3

A capacitor of capacity

2 μ F

is charged to a potential difference of

12 V

. It is then connected across an inductor of inductance

0.6 mH

. The current in the circuit at a time when the P.D. across the capacitor is

6 V

is (in ampere).

View Solution

Q4

Four capacitors and a battery are connected as shown in the figure. If the potential difference across the

7 μ F

capacitor is

6 V

, then which of the following statement(s) is/are correct?

View Solution

Q5

In the given circuit, peak voltage across the resistor and capacitor are 6V and 8V. At an instant when voltage across capacitor is 4V in magnitude,

View Solution